Optimal. Leaf size=374 \[ \frac{2 a^2 \left (11 A d (c-17 d)-3 B \left (c^2-9 c d+56 d^2\right )\right ) \cos (e+f x) (c+d \sin (e+f x))^3}{693 d^2 f \sqrt{a \sin (e+f x)+a}}+\frac{4 a^2 (c+d) \left (15 c^2+10 c d+7 d^2\right ) \left (11 A d (c-17 d)-3 B \left (c^2-9 c d+56 d^2\right )\right ) \cos (e+f x)}{3465 d^2 f \sqrt{a \sin (e+f x)+a}}+\frac{2 a^2 (3 B (c-4 d)-11 A d) \cos (e+f x) (c+d \sin (e+f x))^4}{99 d^2 f \sqrt{a \sin (e+f x)+a}}+\frac{4 (c+d) \left (11 A d (c-17 d)-3 B \left (c^2-9 c d+56 d^2\right )\right ) \cos (e+f x) (a \sin (e+f x)+a)^{3/2}}{1155 f}+\frac{8 a (5 c-d) (c+d) \left (11 A d (c-17 d)-3 B \left (c^2-9 c d+56 d^2\right )\right ) \cos (e+f x) \sqrt{a \sin (e+f x)+a}}{3465 d f}-\frac{2 a B \cos (e+f x) \sqrt{a \sin (e+f x)+a} (c+d \sin (e+f x))^4}{11 d f} \]
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Rubi [A] time = 0.920242, antiderivative size = 374, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 6, integrand size = 37, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.162, Rules used = {2976, 2981, 2770, 2761, 2751, 2646} \[ \frac{2 a^2 \left (11 A d (c-17 d)-3 B \left (c^2-9 c d+56 d^2\right )\right ) \cos (e+f x) (c+d \sin (e+f x))^3}{693 d^2 f \sqrt{a \sin (e+f x)+a}}+\frac{4 a^2 (c+d) \left (15 c^2+10 c d+7 d^2\right ) \left (11 A d (c-17 d)-3 B \left (c^2-9 c d+56 d^2\right )\right ) \cos (e+f x)}{3465 d^2 f \sqrt{a \sin (e+f x)+a}}+\frac{2 a^2 (3 B (c-4 d)-11 A d) \cos (e+f x) (c+d \sin (e+f x))^4}{99 d^2 f \sqrt{a \sin (e+f x)+a}}+\frac{4 (c+d) \left (11 A d (c-17 d)-3 B \left (c^2-9 c d+56 d^2\right )\right ) \cos (e+f x) (a \sin (e+f x)+a)^{3/2}}{1155 f}+\frac{8 a (5 c-d) (c+d) \left (11 A d (c-17 d)-3 B \left (c^2-9 c d+56 d^2\right )\right ) \cos (e+f x) \sqrt{a \sin (e+f x)+a}}{3465 d f}-\frac{2 a B \cos (e+f x) \sqrt{a \sin (e+f x)+a} (c+d \sin (e+f x))^4}{11 d f} \]
Antiderivative was successfully verified.
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Rule 2976
Rule 2981
Rule 2770
Rule 2761
Rule 2751
Rule 2646
Rubi steps
\begin{align*} \int (a+a \sin (e+f x))^{3/2} (A+B \sin (e+f x)) (c+d \sin (e+f x))^3 \, dx &=-\frac{2 a B \cos (e+f x) \sqrt{a+a \sin (e+f x)} (c+d \sin (e+f x))^4}{11 d f}+\frac{2 \int \sqrt{a+a \sin (e+f x)} (c+d \sin (e+f x))^3 \left (\frac{1}{2} a (11 A d+B (c+8 d))-\frac{1}{2} a (3 B (c-4 d)-11 A d) \sin (e+f x)\right ) \, dx}{11 d}\\ &=\frac{2 a^2 (3 B (c-4 d)-11 A d) \cos (e+f x) (c+d \sin (e+f x))^4}{99 d^2 f \sqrt{a+a \sin (e+f x)}}-\frac{2 a B \cos (e+f x) \sqrt{a+a \sin (e+f x)} (c+d \sin (e+f x))^4}{11 d f}-\frac{\left (a \left (11 A (c-17 d) d-3 B \left (c^2-9 c d+56 d^2\right )\right )\right ) \int \sqrt{a+a \sin (e+f x)} (c+d \sin (e+f x))^3 \, dx}{99 d^2}\\ &=\frac{2 a^2 \left (11 A (c-17 d) d-3 B \left (c^2-9 c d+56 d^2\right )\right ) \cos (e+f x) (c+d \sin (e+f x))^3}{693 d^2 f \sqrt{a+a \sin (e+f x)}}+\frac{2 a^2 (3 B (c-4 d)-11 A d) \cos (e+f x) (c+d \sin (e+f x))^4}{99 d^2 f \sqrt{a+a \sin (e+f x)}}-\frac{2 a B \cos (e+f x) \sqrt{a+a \sin (e+f x)} (c+d \sin (e+f x))^4}{11 d f}-\frac{\left (2 a (c+d) \left (11 A (c-17 d) d-3 B \left (c^2-9 c d+56 d^2\right )\right )\right ) \int \sqrt{a+a \sin (e+f x)} (c+d \sin (e+f x))^2 \, dx}{231 d^2}\\ &=\frac{4 (c+d) \left (11 A (c-17 d) d-3 B \left (c^2-9 c d+56 d^2\right )\right ) \cos (e+f x) (a+a \sin (e+f x))^{3/2}}{1155 f}+\frac{2 a^2 \left (11 A (c-17 d) d-3 B \left (c^2-9 c d+56 d^2\right )\right ) \cos (e+f x) (c+d \sin (e+f x))^3}{693 d^2 f \sqrt{a+a \sin (e+f x)}}+\frac{2 a^2 (3 B (c-4 d)-11 A d) \cos (e+f x) (c+d \sin (e+f x))^4}{99 d^2 f \sqrt{a+a \sin (e+f x)}}-\frac{2 a B \cos (e+f x) \sqrt{a+a \sin (e+f x)} (c+d \sin (e+f x))^4}{11 d f}-\frac{\left (4 (c+d) \left (11 A (c-17 d) d-3 B \left (c^2-9 c d+56 d^2\right )\right )\right ) \int \sqrt{a+a \sin (e+f x)} \left (\frac{1}{2} a \left (5 c^2+3 d^2\right )+a (5 c-d) d \sin (e+f x)\right ) \, dx}{1155 d^2}\\ &=\frac{8 a (5 c-d) (c+d) \left (11 A (c-17 d) d-3 B \left (c^2-9 c d+56 d^2\right )\right ) \cos (e+f x) \sqrt{a+a \sin (e+f x)}}{3465 d f}+\frac{4 (c+d) \left (11 A (c-17 d) d-3 B \left (c^2-9 c d+56 d^2\right )\right ) \cos (e+f x) (a+a \sin (e+f x))^{3/2}}{1155 f}+\frac{2 a^2 \left (11 A (c-17 d) d-3 B \left (c^2-9 c d+56 d^2\right )\right ) \cos (e+f x) (c+d \sin (e+f x))^3}{693 d^2 f \sqrt{a+a \sin (e+f x)}}+\frac{2 a^2 (3 B (c-4 d)-11 A d) \cos (e+f x) (c+d \sin (e+f x))^4}{99 d^2 f \sqrt{a+a \sin (e+f x)}}-\frac{2 a B \cos (e+f x) \sqrt{a+a \sin (e+f x)} (c+d \sin (e+f x))^4}{11 d f}-\frac{\left (2 a (c+d) \left (15 c^2+10 c d+7 d^2\right ) \left (11 A (c-17 d) d-3 B \left (c^2-9 c d+56 d^2\right )\right )\right ) \int \sqrt{a+a \sin (e+f x)} \, dx}{3465 d^2}\\ &=\frac{4 a^2 (c+d) \left (15 c^2+10 c d+7 d^2\right ) \left (11 A (c-17 d) d-3 B \left (c^2-9 c d+56 d^2\right )\right ) \cos (e+f x)}{3465 d^2 f \sqrt{a+a \sin (e+f x)}}+\frac{8 a (5 c-d) (c+d) \left (11 A (c-17 d) d-3 B \left (c^2-9 c d+56 d^2\right )\right ) \cos (e+f x) \sqrt{a+a \sin (e+f x)}}{3465 d f}+\frac{4 (c+d) \left (11 A (c-17 d) d-3 B \left (c^2-9 c d+56 d^2\right )\right ) \cos (e+f x) (a+a \sin (e+f x))^{3/2}}{1155 f}+\frac{2 a^2 \left (11 A (c-17 d) d-3 B \left (c^2-9 c d+56 d^2\right )\right ) \cos (e+f x) (c+d \sin (e+f x))^3}{693 d^2 f \sqrt{a+a \sin (e+f x)}}+\frac{2 a^2 (3 B (c-4 d)-11 A d) \cos (e+f x) (c+d \sin (e+f x))^4}{99 d^2 f \sqrt{a+a \sin (e+f x)}}-\frac{2 a B \cos (e+f x) \sqrt{a+a \sin (e+f x)} (c+d \sin (e+f x))^4}{11 d f}\\ \end{align*}
Mathematica [A] time = 4.59295, size = 390, normalized size = 1.04 \[ -\frac{a \sqrt{a (\sin (e+f x)+1)} \left (\cos \left (\frac{1}{2} (e+f x)\right )-\sin \left (\frac{1}{2} (e+f x)\right )\right ) \left (-8 \left (11 A d \left (189 c^2+351 c d+137 d^2\right )+3 B \left (1287 c^2 d+231 c^3+1507 c d^2+581 d^3\right )\right ) \cos (2 (e+f x))+70 d^2 (11 A d+33 B c+21 B d) \cos (4 (e+f x))+99792 A c^2 d \sin (e+f x)+216216 A c^2 d+18480 A c^3 \sin (e+f x)+92400 A c^3+100188 A c d^2 \sin (e+f x)-5940 A c d^2 \sin (3 (e+f x))+195624 A c d^2+35156 A d^3 \sin (e+f x)-3740 A d^3 \sin (3 (e+f x))+59158 A d^3+100188 B c^2 d \sin (e+f x)-5940 B c^2 d \sin (3 (e+f x))+195624 B c^2 d+33264 B c^3 \sin (e+f x)+72072 B c^3+105468 B c d^2 \sin (e+f x)-11220 B c d^2 \sin (3 (e+f x))+177474 B c d^2+34734 B d^3 \sin (e+f x)-4935 B d^3 \sin (3 (e+f x))+315 B d^3 \sin (5 (e+f x))+55482 B d^3\right )}{27720 f \left (\sin \left (\frac{1}{2} (e+f x)\right )+\cos \left (\frac{1}{2} (e+f x)\right )\right )} \]
Antiderivative was successfully verified.
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Maple [A] time = 1.015, size = 312, normalized size = 0.8 \begin{align*}{\frac{ \left ( 2+2\,\sin \left ( fx+e \right ) \right ){a}^{2} \left ( -1+\sin \left ( fx+e \right ) \right ) \left ( 315\,B \left ( \cos \left ( fx+e \right ) \right ) ^{4}\sin \left ( fx+e \right ){d}^{3}+ \left ( -1485\,Ac{d}^{2}-935\,A{d}^{3}-1485\,B{c}^{2}d-2805\,Bc{d}^{2}-1470\,B{d}^{3} \right ) \left ( \cos \left ( fx+e \right ) \right ) ^{2}\sin \left ( fx+e \right ) + \left ( 1155\,A{c}^{3}+6237\,A{c}^{2}d+6633\,Ac{d}^{2}+2431\,A{d}^{3}+2079\,B{c}^{3}+6633\,B{c}^{2}d+7293\,Bc{d}^{2}+2499\,B{d}^{3} \right ) \sin \left ( fx+e \right ) + \left ( 385\,A{d}^{3}+1155\,Bc{d}^{2}+735\,B{d}^{3} \right ) \left ( \cos \left ( fx+e \right ) \right ) ^{4}+ \left ( -2079\,A{c}^{2}d-3861\,Ac{d}^{2}-1892\,A{d}^{3}-693\,B{c}^{3}-3861\,B{c}^{2}d-5676\,Bc{d}^{2}-2478\,B{d}^{3} \right ) \left ( \cos \left ( fx+e \right ) \right ) ^{2}+5775\,A{c}^{3}+14553\,A{c}^{2}d+14157\,Ac{d}^{2}+4499\,A{d}^{3}+4851\,B{c}^{3}+14157\,B{c}^{2}d+13497\,Bc{d}^{2}+4431\,B{d}^{3} \right ) }{3465\,f\cos \left ( fx+e \right ) }{\frac{1}{\sqrt{a+a\sin \left ( fx+e \right ) }}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (B \sin \left (f x + e\right ) + A\right )}{\left (a \sin \left (f x + e\right ) + a\right )}^{\frac{3}{2}}{\left (d \sin \left (f x + e\right ) + c\right )}^{3}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.98949, size = 1667, normalized size = 4.46 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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